Respostas

2014-03-19T12:49:09-03:00
{Bhaskara}={-b +ou- √Δ / 2*a}{Δ=b²-4*a*c}
X²-6X-16=0 {A=1 , B=-6 , C=-16}
Δ=(-6)²-4*1*16
Δ=36+64
Δ=100
√100=10

-b +ou- √Δ/2.a
-(-6) +ou- 10 /2*1
x'=+6 + 10 /2 = 16/2 = 8
x''= +6 - 10/2= -4/2 = -2

{x'+x''/2}
8+(-2)/2
6/2 =3 <<<A

 {1/x'+1/x''}
1/8+1/(-2)
MMC de 8,-2 = 8
8/8*1=1
8/(-2)*1=(-4)
1+(-4)=-3/8 <<<B

{3(x' * x''}}
3(8*(-2))
3*(-16)
-48 <<<C
3 4 3