Respostas

2014-03-20T06:11:58-03:00
Fazendo distancia entre pontos...

d(AB) =\sqrt{(0-1)^2+(1-2)^2+(1-(-1)^2}= \sqrt6
d(AC)= \sqrt{(2-1)^2+(0-2)^2+(0-(-1)^2}= \sqrt6
d(BC)= \sqrt{(0-2)^2+(1-0)^2+(1-0)^2}= \sqrt6