Respostas

  • Usuário do Brainly
2013-02-08T00:44:17-02:00

Observemos que:

 

0,19=\dfrac{19}{100}

 

0,8=\dfrac{8}{10}

 

0,5=\dfrac{5}{10}

 

Seja \text{X}=\dfrac{1}{4}+\dfrac{19}{100}\div(4-\dfrac{8}{10}\div\dfrac{5}{10}-\dfrac{1}{2})

 

Desta maneira, temos:

 

\text{X}=\dfrac{1}{4}+\dfrac{19}{100}\div(4-\dfrac{8}{5}-\dfrac{1}{2})

 

Donde, obtemos:

 

\text{X}=\dfrac{1}{4}+\dfrac{19}{100}\div\dfrac{19}{10}

 

Contudo, podemos afirmar que:

 

\text{X}=\dfrac{1}{4}+\dfrac{1}{10}

 

\text{X}=\dfrac{5+2}{20}=\dfrac{7}{20}

2 1 2
2013-02-08T12:21:41-02:00
1/4+0,19(4-0,8:0,5-1/2) = 1/4+19/100:(4-8/10:5/10-1/2) = 1/4+19/100:(19/10)1/4+1/10=7/20        obs:0,19=19/100                                     0,8=8/10              0,5=5/10                                           a resposta é 7/20 
1 5 1