Respostas

2013-05-27T14:25:34-03:00

Calculando o delta:

Δ = b²- 4.a.c 
Δ = (-8)² - 4 . 2 . 6 
Δ = 64 - 4. 2 . 6 
Δ = 16

 

Aplicando a fórmula de Bhaskara:

x = (-b +- √Δ)/2a

x' = (-8 + √16)/2.2

x' =  12 / 4

x' = 3

 

x'' = -(-8 - √16)/2.2

x'' = 4 / 4

x'' = 1

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2013-05-27T14:26:08-03:00

Δ = b²- 4.a.c 

Δ = (-8)²-4.2.6

Δ = 64 - 48

Δ = 16

 

x = (-b +- √Δ)/2a

x= (-(-8) =- x = √16 /2.2

x= 8 +- 4 /4

 

x¹= 8+4/4= 12/4 = -3

 

x²= 8-4/4 = 4/4 = 1

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