Respostas

  • Usuário do Brainly
2013-05-27T15:46:29-03:00

\text{x}=\dfrac{-\text{b}\pm\sqrt{\text{b}^2-4\cdot\text{a}\cdot\text{c}}}{2\cdot1}

 

onde, \text{a}=1, \text{b}=-3 e \text{c}=-10

 

Logo:

 

\text{x}=\dfrac{-(-3)\pm\sqrt{3^2-4\cdot1\cdot(-10)}}{2\cdot1}=\dfrac{3\pm\sqrt{49}}{2}

 

Portanto, as raízes são:

 

\text{x}'=\dfrac{3+7}{2}=5

 

\text{x}''=\dfrac{3-7}{2}=-2

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