Respostas

  • Usuário do Brainly
2013-05-27T15:03:21-03:00

Temos que:

 

\text{x}^2-\dfrac{\text{x}}{2}=\text{x}-\text{x}-\dfrac{\text{x}^2}{3}

 

6\text{x}^2-3\text{x}=2\text{x}^2

 

4\text{x}^2-3\text{x}=0

 

\text{x}\cdot(4\text{x}-3)=0

 

Logo, as raízes são:

 

\text{x}'=0

 

\text{x}''=\dfrac{3}{4}