Respostas

2014-04-06T11:05:40-03:00
a) y = cos x³
 
u=x³   u'=3x²

f(x)= -sen

f '(x)= -sen.x³.3x²
logo:
f '(x)= -3x².sen.x³


b) y = sen³ x => (sen x)³

u= sen x   u'=cosx

f(x)=(u)³

f '(x)= 3. (sen x)³-¹.(cosx)

f '(x)= 3. (sen x)².(cosx)

f '(x)= 3.sen ² x .cosx

f '(x)= 3.cosx.sen ²x

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