Respostas

2014-04-09T10:22:05-03:00
 3x^{2} -2x-1=0

A=3
B=-2
C=-1

Δ=b²-4·a·c
Δ=(-2)²-4·1·(-1)
Δ=16

 \frac{-b +ou - \sqrt{Delta} }{2*a}

 \frac{2+ \sqrt{16} }{6} = 1

 \frac{2- \sqrt{16} }{6}  \frac{-1}{3}

1 5 1