Respostas

  • Usuário do Brainly
2013-06-03T18:58:57-03:00

Temos que:

 

\text{q}=\dfrac{\text{a}_2}{\text{a}_1}=\dfrac{\text{a}_3}{\text{a}_2}=\dfrac{-24}{-48}=\dfrac{-12}{-24}=\dfrac{1}{2}

 

Logo:

 

\text{a}_{\text{n}}=\text{a}_1\cdot\text{q}^{\text{n}-1}

 

\text{a}_{10}=-48\cdot\left(\dfrac{1}{2}\right)^{10-1}

 

\text{a}_{10}=-48\cdot\left(\dfrac{1}{2}\right)^9

 

\text{a}_{10}=-48\cdot\dfrac{1}{512}

 

\text{a}_{10}=\dfrac{-48}{512}=\dfrac{-3}{32}

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