Respostas

2014-04-09T20:23:06-03:00
3 x^{2} -x+5=-2x+9

3 x^{2} +x-4=0

Δ = 1-4.3.(-4)=1+48=49

 x_{1} = \frac{-1+ \sqrt{49} }{2.3} =\frac{-1+ 7 }{6}= \frac{6}{6} =1
ou
 x_{2} = \frac{-1- \sqrt{49} }{2.3} =\frac{-1- 7 }{6}= \frac{-8}{6} =- \frac{4}{3}

Para x = 1 ⇒ f(x)=g(x)=-2.1+9=9-2=7

Para x = - \frac{4}{3} f(x)=g(x)=-2. (-\frac{4}{3} )+9= \frac{8}{3} +9 =\frac{8+27}{3} = \frac{35}{3}
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