Respostas

2014-04-14T13:34:08-03:00
 U = (3, -1, 2)
 V = (-2, 2, 1)

  \left[\begin{array}{ccc}i&j&k\\3&-1&2\\-2&2&1\end{array}\right]   \left\begin{array}{cc}i&j\\3&-1\\-2&2\end{array}\right] \\\\\ i=(-1-4)=-5\\\\j=(-4-3)=-7\\\\k=(6-2)=4\\\\\\\\\ (-5 ;-7;4)

calculando o modulo disso
 \sqrt{(-5)^2+(;-7)^2+(4)^2} \\\\ \sqrt{25+49+16} \\\\ \sqrt{90}

a área desse paralelogramo vale 
√90
1 5 1