Respostas

2013-06-05T21:54:18-03:00

p^2+6p=2\\p^2+6p-2=0

vou substituir p por X para ficar melhor de resolver por bhaskara. questao de costume..kkk vamos la;

 

x^2+6x-2=0\\\\x=\frac{-b^+_-\sqrt{b^2-4ac}}{2a}\\x=\frac{-6^+_-\sqrt{6^2-4*1*(-2)}}{2*1}\\x=\frac{-6^+_-\sqrt{36+8}}{2}\\x=\frac{-6^+_-\sqrt44}{2}\\x=\frac{-6^+_-2\sqrt11}{2}\\\\x'=\frac{-6+2\sqrt11}{2}\\\\x'=-3+\sqrt11\\\\x''=\frac{-6-2\sqrt11}{2}\\x''=-3-\sqrt11\\\\S=(-3+\sqrt11, -3-\sqrt11)

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