Respostas

  • Usuário do Brainly
2014-04-29T14:23:22-03:00
J(- 2, - 1)
K(3, - 4)

d (J, K) = √(x2 - x1)² + (y2 - y1)²
d (J, K) = √(3 - (- 2))² + (- 4 - (- 1))²
d (J, K) = √(3 + 2)² + (- 4 + 1)²
d (J, K) = √5² + (- 3)²
d (J, K) = √25 + 9
d (J, K) = √34
6 3 6