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A melhor resposta!
2014-05-01T16:40:31-03:00
Deriva o numerador e denominador

 \lim_{x \to- \frac{3}{2} } \frac{12x+11}{4x-5}

\boxed{ \lim_{x \to- \frac{3}{2} } \frac{12(- \frac{3}{2} )+11}{4(- \frac{3}{2} )-5} = \frac{-7}{-11} ~\to~ \frac{7}{11} }
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