Respostas

2014-05-07T18:33:58-03:00
2014-05-07T18:45:23-03:00
Diferença de dízimas periódicas 

1° dízima

x=0,666..
 x=\frac{2}{3}

2° dízima

y=0,0666...*(100)
100y=6,666..
100y=6+ \frac{2}{3}
100y=6+ \frac{2}{3} \\
\\100y= \frac{20}{3} \\300y=20\\
\\y= \frac{1}{15}

Diferença

x-y

\boxed{ \frac{2}{3} - \frac{1}{15} = \frac{10-1}{15} = \frac{9^{\div3}}{15^{\div3}} ~\to~ \frac{3}{5}~~ou~0,6}