Respostas

2013-06-18T15:30:33-03:00

==>Dados:
abcd tais que
b = (1/3)a
c = b + d
d = (1/3)b

==>Resolução:
d = (1/3(1/3)a = (1/9)a
c = b + (1/3)b = (3b + b)/3 = (4/3)b
c = (4/3) (1/3)a = (4/9)a

Ficamos com
a
b = (1/3)a = (1/3)a (3/3) = (3/9)a
c = (4/9)a
d = (1/9)a
Podemos fazer 
a = 1.a = (9/9)a

Então
a = 9
b = 3
c = 4
d = 1

==>Confirmando:
a = 9
b = (1/3)a = (1/3) . 9 = 3
c = b + d = 3 + 1 = 4
d = (1/3)b = (1/3) . 3 = 1

==>Resposta:
Portanto, abcd = 9341

 

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