Respostas

2014-05-12T19:42:01-03:00
1 mol ---- 6,02.10²³ átomos 

Sacarose = C12H22O11

MM = C12H22O11 = 342 g / mol

3,42 kg = 3420 g


6,02.10²³ átomos  ----------- 342g
   x ---------------------------------3420g

x = 6,02 .10²⁴ átomos