Respostas

2014-05-14T13:19:30-03:00
3x²-24x+48=0
D=b²-4ac
D=(-24)²-4.(3).(48)
D=576-576
D=0

x= -b+- raiz D/2a
x= -(-24) +-0
          2.3

x= 24/6
x=4
2014-05-14T13:36:58-03:00

Se a questão for: 3x² - 24x + 48 = 0

Δ= b² - 4.a.c
Δ= (24)² - 4.3.48
Δ= 576 - 576
Δ= 0

x= -b+- √Δ /2.a
x= -(-24) +- Δ0 / 2.3
x= 24 + 0 / 6

x'= 24 - 0 / 6
x'= 4

x''= 24 + 0 / 6
x''= 4