Respostas

2014-05-16T01:49:44-03:00
√32+4√8-√50-(√2)³
 \sqrt{32}= \sqrt{2^5}=\sqrt{2^4*2}=4 \sqrt{2}
4 \sqrt{8}=4 \sqrt{2^3}  =4 \sqrt{2^2*2} =8 \sqrt{2}
 \sqrt{50}= \sqrt{2*5^2}=5 \sqrt{2}
 \sqrt{2}^3= \sqrt{2^3}= \sqrt{2^2*2}=2 \sqrt{2}

então, 
\sqrt{32}+4 \sqrt{8}- \sqrt{50}-( \sqrt{2})^3   =4 \sqrt{2}+8 \sqrt{2} -5 \sqrt{2}-2 \sqrt{2}=5 \sqrt{2}