Respostas

2014-05-16T22:44:33-03:00
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\int (8x - 3)^{7}dx = \\\\
u = 8x -3 \\\\
du  =8 dx \to  dx = \frac{du}{8} \\\\
\int (u)^{7}\frac{du}{8} = \\\\
 \frac{1}{8}\int u^{7}du = \\\\
\frac{1}{8} \frac{u^{7 + 1}}{7+1} + c =  \frac{1}{8}  \frac{u^{8}}{8}+c = \\\\
 \boxed{\frac{1}{64}  u^{8} + c}=>\boxed{\boxed{\frac{1}{64}  (8x - 3)^{8} + c}}
Letra (c)