Respostas

2014-05-21T21:14:47-03:00
(x+2).(x-6)=0
x²-6x+2x-12=0
x²-4x-12=0

a=1; b=-4 e c=-12
Δ=b²-4.a.c
Δ=(-4)²-4.1.(-12)
Δ=16+48
Δ=64
x=-b+-√Δ/2.a
x=-(-4)+-√64/2.1
x=4+-8/2
x'=4+8/2=12/2=6
x"=4-8/2=-4/2=-2
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