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2014-05-27T12:43:57-03:00
2x^2 - 16 = 0 \\ 2x^2= 16 \\  \\ x^2 =  \frac{16}{2}  \\  \\ x^2 = 8 \\ x =  \sqrt{8} \\  x=2,83 aproximadamente.


x^2-16x=0

Δ = (-16)^2-4.1.0
Δ = 256 - 0
Δ = 256

X =  \frac{-(-16)+- \sqrt{256} }{2.1} =>X =  \frac{16+-16}{2}

x' =  \frac{16+16}{2} =>  \frac{32}{2} = 16                         x" =  \frac{16-16}{2} => \frac{0}{2} = 0

;D
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