Respostas

2014-05-29T03:25:42-03:00
3 x^2 -3+2x/2x+3 = 0/2x+3 (mmc) \\
3 x^{2} +2x-3=0
Δ=b^2-4ac
Δ=16
x= -b +/- √Δ/2a
x= -2 +/- 4/6
x'=2/6
x''= -1
3 5 3