Respostas

2014-05-31T20:17:48-03:00
A = (aij)1x3 tal que aij = 2i – j 

[a11  a12  a13]

aij = 2i – j 
a11 = 2.1-1 = 2 -1 = 1
a12 = 2.1-2 = 2 - 2 = 0
a13 = 2.1-3 = 2 - 3 = -1

[1  0  -1]


B= (bij)1x3 tal que bij = -i + j + 1

[b11 b12 b13]

bij = -i + j + 1
b11 = -1 + 1 + 1 = 1
b12 = -1 + 2 + 1 = 2
b13 = -1 + 3 + 1 = 3

[1   2   3]

A + B 

[1  0  -1] + [1   2   3] = [2   2  2]
2 5 2