Respostas

2014-06-03T11:55:14-03:00
F(x)= cotg(x²(x+3)  
f '(x)= -(x²(x+3))' cosec²(x²(x+3))   << na tabela -u'cosec²u

f '(x)= -(x³+3x²)' cosec²(x²(x+3))   <<< resolve distributiva


f ' (x)= - (3x² + 6x) cosec²(x²(x+3))   <<<<   derivada    ou

f'(x)= -3x² cosec² (x²(x+3)) - 6x cosec² (x²(x+3))