Respostas

2013-07-07T16:35:18-03:00
Simples
3z^2-15z+12=0
a=3
b=-15
c=12
▲=b^2-4ac
▲=(-15)^2-4.3.12
▲=81

x'=(-b+√▲)/2a
=15+√81/2.3
=(15+9)/6
=4

x"=(15-9)/6
x"=6/6
=1