Respostas

2014-06-05T17:05:05-03:00
3x^2-7x+4=0
Δ=b^2-4.a.c
Δ=(-7)^2-4.3.4
Δ=49-48
Δ=1

x=-b+ou-√Δ/2.a
x=-(-7)+ou-√1/2.3

x=7+ou-1/6

x=7+1/6=1,33                  x=7-1/6=0