Respostas

2013-07-14T21:19:24-03:00
Duas faces triangulares =2*3=6
Duas quadrangulares=2*4=8
Quatro pentagonais=4*5=20

6+8+20=2A

34=2A

A=17

V+F=A+2

V+8=17+2

V=11

Soma dos ângulos 

S=(V-2)*4r

S=(11-2)*4*90°

S=9*4*90

S=3240°
5 4 5