Respostas

2014-06-28T13:14:16-03:00
A derivada de cosx = - senx e a de senx = cosx

Seja f(x) = cos5x/sen2x, sua derivada é:

f '(x) = [sen2x( - sen5x) · 5 - cos5x( cos2x ) · 2]/ ( sen2x )²
f '(x) =  - 5sen2xsen5x - 2cos5xcos2x/ sen²2x
2 5 2