Respostas

2014-06-30T00:28:39-03:00
2014-06-30T01:36:19-03:00
 \frac{1-tgx}{1-cotgx}

 \frac{1- \frac{senx}{cosx} }{1- \frac{cosx}{senx} } = \frac{ \frac{cosx-senx}{cosx} }{ \frac{senx-cosx}{senx} } = \frac{cosx-senx}{cosx}. \frac{senx}{senx-cosx}=

senx=3/5
sen²x+cos²x=1
cos²x=1-sen²x
temos
[tex] \frac{senx-cosx}{cosx}. \frac{senx}{cosx-senx}=