Respostas

2013-07-28T11:32:41-03:00
A.b = [4logx(base2) + 4log2x(base2)]
        [4y+2y                                   ]

Igualando aos valores de c teremos:

28 = 4(logx(base2) + log2x(base2))
Usando as propriedades do logaritmo: log(ab) = loga + logb

7 = logx(base2) + log2(base2) + logx(base2)
6 = 2logx(base2)
3 = logx(base2)
x = 8

6y = 10
y = 5/3

Logo x = 8 e y = 5/3