Respostas

2014-07-16T23:13:24-03:00
Y = ∛(6x² + 7x + 2)

Reescrevendo a função

y = (6x² + 7x + 2)^1/3

Derivando

y' = (1/3)(6x² + 7x + 2)^(1/3 - 1) · (12x + 7)
y' = (1/3)(6x² + 7x + 2)^(-2/3) · (12x + 7)
y' = (12x + 7)/3∛(6x² + 7x + 2)²
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