Respostas

2014-07-21T15:03:28-03:00
-x²+x+12=0
-x²=12-0
x²=12

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A melhor resposta!
2014-07-21T15:09:24-03:00
-x²+x+12+0
a=-1 b=1 c=12
 Aplica-se a formula de Bhaskara.
-b+-√b²-4ac/2a=
-1+-√1²-4*(-1)*12/2*1=
-1+-√1+48/2
-1+-√49/2=
-1+-7/2=
x1=-1+7/2=6/2=3
x2=-1-7/2=-8/2=-4

S=(3;-4)
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