Respostas

  • Usuário do Brainly
2014-07-27T16:29:20-03:00
8.n! = (n+2).(n+1).n! +(n+1).n! / n+1
8.n! = (n+1) [(n+2).n! + n! ] / n+1
8.n! = n!.(n+2)+n!
8 = n+1 + 1
n+2=8
n=6
2014-07-27T16:40:52-03:00
(n+2)!=(n+2)(n+1)n!
(n+1)!=(n+1)n!
8n!=((n+2)(n+1)n!+(n+1)n!)/n+1
simplifica o n+1 e o n!
fica 8=n+2+1
n=5
2 3 2