Respostas

2014-07-30T10:51:19-03:00
Fazendo :

\boxed{ \left \{ {{x^4=y^2} \atop {x^2=y}} \right. }

Aplicando ;

y^2-10y+24=0\\
\\\Delta=(-10)^2-4*1*24\\\Delta=100-96
\\\Delta=4

y= \frac{10\pm2}{2} \\
\\y'=6\\
\\y''=4

determinar as raízes

x= \sqrt{y'}\\
\\x= \sqrt{y''}

x= \pm\sqrt{6} \\
\\x=\pm2

S=\{2,+2,- \sqrt{6},+ \sqrt{6}  }}