Respostas

2014-08-01T12:28:55-03:00
 \left \{ {{3x=17,40} \atop {x+2y=22,5}} \right.

x=\boxed{\frac{17,4}{3}}

 \frac{17,4}{3} +2y=22,5

2y=22,5- \frac{17}{3}

2y= \frac{67,5-17,4}{3}

2y= \frac{67,5}{3}

2y=16,7

y= \frac{16,7}{2}

\boxed{y=8,35}

Logo, o lado do triângulo equilátero vale x=5,8, e o lado do retângulo vale y=8,35 e x=5,8.
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