Respostas

2014-08-04T21:20:36-03:00
A) o comprimento final da barra a 20°c 
L=lo[1+α*Δt]
L=10[1+0,000012*20]
L=10[1+0,00024]
L=10[1,00024] 
L=10,0024m  
B) O comprimento final da barra a 30°c 
L=lo[1+α*Δt]
L=10[1+0,000012*30]
L=10[1+0,00036]
L=10[1,00036] 
L=10,0036m