Escreva as equecoes a seguir na forma ax²+bx+c=0 e, em seguida, determine os coeficientes A,B e C ( respostas completas ) :D
a) (3x+1)² = ( x+8) (x-3)

b) x(x-6) + x² = (x+5) (x+2)

c) x + 6 = 4x, x diferente de 2
x-1

d) (-2x-1)(x-2) = 3x+ 5x²

e) (2x+1) (2x-1) = 5x+3

f) 2x² + (x+2) x =4

g) (x+3) (x-4) = (2x+1)²


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Respostas

2014-08-06T15:18:27-03:00
a) (3x+1)² = ( x+8) (x-3)
9x+1=x2-3x+8x-24
-x2+9x+3x-8x+1+24=0
-x2+4x+25=0
a= -1 b= +4 c= +25

b) x(x-6) + x² = (x+5) (x+2)
x2-6x+ x2= x2+2x+5x+10
x2+ x2- x2-6x-2x-5x-10=0
x2-13x-10=0
a=1 b=-13 c=-10


d) (-2x-1)(x-2) = 3x+ 5x² 
-2x2+4x-x+2=3x+5x2
- 2x2-5x2+4x-x-3x+2=0
-7x2+x+2=0
a=-7 b=0 c=2


e) (2x+1) (2x-1) = 5x+3
4x2-2x+2x-1=5x+3
4x2-2x+2x-1-5x-3=0
4x2-5x-4=0
a=4 b=-5 c=-4


f) 2x² + (x+2) x =4 
2x2+x2+2x=4
3x2+2x-4=0
a=3 b=2 c=-4


g) (x+3) (x-4) = (2x+1)²
x2-4+3x-12=4x+1
x2-4x+3x-4x-12-1=0
x2-5x-13=0
a=1 b=-5 c=-13

nao entendi a letra C mas espero ter ajudado
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