Respostas

2014-08-07T15:38:58-03:00
x^2-2x-15=0\\
\Delta=(-2)^2-4*1*(-15)\\
\Delta=4+60\\
\Delta=64\\
x=\dfrac{-(-2)\pm \sqrt{64} }{2*1}\\\\
x'=\dfrac{2+8}{2}=\boxed{5}\\\\
x''\dfrac{2-8}{2}=\boxed{-3}\\\\
\ [-3,~5] = \{-2,-1,0,1,2,3,4\}

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