Respostas

2014-08-10T17:31:34-03:00
\sqrt{5x-7}=\sqrt{3x+15} [tex](\sqrt{5x-7})^{2}=(\sqrt{3x+15})^{2} [tex]5x-3x=15+7
2x=22
x=\frac{22}{2}
x=11

[tex]\sqrt{5x-7}=\sqrt{3x+15}[tex]
[tex]\sqrt{5*11-7}=\sqrt{3*11+15}[tex]
[tex]\sqrt{55-7}=\sqrt{33+15}[tex]
[tex]\sqrt{48}=\sqrt{48}[tex]

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