Respostas

  • Usuário do Brainly
2014-08-14T00:00:46-03:00
 x^{2} = \frac{4x}{5} + \frac{1}{5}

 \frac{5 x^{2} =4x+1}{5}

5 x^{2} -4x-1=0

Δ=b²-4ac
Δ=16+20
Δ=36
√Δ=√36
√36 = ± 6

x'= \frac{4+6}{2} = \frac{10}{2} =5

x"= \frac{4-6}{2} =- \frac{2}{10} =- \frac{1}{5}

S={  \frac{1}{5} ,5}