Respostas

2014-08-20T11:30:32-03:00
As raizes fazem com que f(x) seja zero

f(x)=x^{2}-6x+5\\0=x^{2}-6x+5

Temos a = 1, b = -6 e c = 5

\Delta=b^{2}-4ac\\\Delta=(-6)^{2}-4.1+5\\\Delta=36-20\\\Delta=16

Fórmula de bhaskara:

x=(-b\pm\sqrt{\Delta})/2a\\x=(-[-6]\pm\sqrt{16})/(2.1)\\x=(6\pm4)/2\\\\x'=(6+4)/2=10/2=5\\x''=(6-4)/2=2/2=1
1 5 1