Respostas

2014-08-23T07:55:07-03:00
Bom dia,

2x² +x-5=0
Δ=b²-4.a.c
a=2,b=1, c=-5
Δ=1²-4.2.-5
Δ=1+40
Δ=41

x=  \frac{-b+- \sqrt{delta} }{2.a}


√41=aproximadamente 6,4

x1= \frac{-1+6,4}{4} = \frac{5,4}{4} =1,35


x2=
 \frac{-1-6,4}{4} ==-7,4/4=-1,85

s=(x2=-1,85, x1=1,35)