Respostas

  • Usuário do Brainly
2014-08-22T14:21:36-03:00
2014-08-22T14:25:14-03:00
X^2-cx-6c^2

a=1
b=-c
c=-6c^2

Achando delta
delta=b^2-4ac
delta= (-c)^2-4.1.(-6c^2)
delta=c^2+24c^2
delta=c^2.(1+24)
delta=25c^2

aplicando baskara:
x=[-b+-raiz(delta)]/2a

x=[-(-c)+-raiz(25c^2)]/2.1
x=( c+-5c)/2
x'=(c+5c)/2=6c/2=3c
x"=(c-5c)/2=-4c/2=-2c

raízes para a equação s={-2c; 3c}