Respostas

2014-08-22T16:46:55-03:00
Z= (x+3i) * (1+xi)
Z= x+x²i+3i-3x
Z= -2x+(x²+3)
Z= -2-(x²+3)i
Z= 2-(4)i

{-2x=2.....=> x' = -1
2 3 2