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2014-08-23T15:43:03-03:00
Olá !
(1 + i)^{11} = (1 + i)^{2}.(1 + i)^{2}.(1 + i)^{2}.(1 + i)^{2}.(1 + i)^{2}.(1 + i) = \\\\
\tt{Como } (1 + i)^{2} = 2i\\\\
\tt{logo,}\\\\
(1 + i)^{11} = 2i.2i.2i.2i.2i(1 +i)\\\\
(1 + i)^{11} = 32i^{5}(1+i)\\\\
(1 + i)^{11} = 32i(1+i) =  \boxed{32 + 32i}\\\\
{\boxed{\boxed{b = 32}}
2 5 2