Respostas

  • Usuário do Brainly
2013-08-17T21:55:07-03:00
Seja \text{q}=\dfrac{40\text{x}^2-20\text{x}-3\text{ax}}{-10\text{x}}.

Note que, \dfrac{40\text{x}^2}{-10\text{x}}=-4\text{x}.

Depois disso, vemos que, \dfrac{-20\text{x}}{-10\text{x}}=2.

Logo, \text{q}=\dfrac{40\text{x}^2-20\text{x}-3\text{ax}}{-10\text{x}}=-4\text{x}+2.

Escrevemos assim: 40\text{x}^2-20\text{x}-3\text{ax}=(-10\text{x})\cdot\text{q}-3\text{ax}