Respostas

  • Usuário do Brainly
2014-09-02T04:44:46-03:00
Ângulos complementares somam 90^{\circ}.

a) 20^{\circ}

\alpha+20^{\circ}=90^{\circ}

\alpha=90^{\circ}-20^{\circ}

\alpha=70^{\circ}


b) 15^{\circ}30'

\beta+15^{\circ}30'=90^{\circ}

\beta=90^{\circ}-15^{\circ}30'

90^{\circ}=89^{\circ}60':

\beta=89^{\circ}60'-15^{\circ}30'

\bera=84^{\circ}30'


c) 81^{\circ}18'48"

\gamma+81^{\circ}18'48"=90^{\circ}

\gamma=90^{\circ}-81^{\circ}18'48"

90^{\circ}=89^{\circ}59'60"


\gamma=89^{\circ}59'60"-81^{\circ}18'48"=8^{\circ}41'12"


d) 67^{\circ}45'

\theta+67^{\circ}45'=90^{\circ}

\theta=90^{\circ}-67^{\circ}45'

90^{\circ}=89^{\circ}60'

\theta=89^{\circ}60'-67^{\circ}45'

\theta=22^{\circ}15'


e) 40^{\circ}

\delta+40^{\circ}=90^{\circ}

\delta=90^{\circ}-40^{\circ}


\delta=50^{\circ}


f) 80^{\circ}

80^{\circ}+\omega=90^{\circ}

\omega=90^{\circ}-80^{\circ}

\omega=10^{\circ}


g) 85^{\circ}

85^{\circ}+\Omega=90^{\circ}

\Omega=90^{\circ}-85^{\circ}

\Omega=15^{\circ}
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