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  • Usuário do Brainly
2014-09-02T06:18:13-03:00
\dfrac{n+3}{n-1}=\dfrac{n-1+4}{n-1}=\dfrac{n-1}{n-1}+\dfrac{4}{n-1}=1+\dfrac{4}{n-1}

n-1 deve dividir 4;

n-1=-1n=0

n-1=-2n=-1

n-1=-4n=-3

n-1=1,   n=2

n-1=2,   n=3

n-1=4n=5

2 5 2