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2013-08-19T23:29:30-03:00
  \left[\begin{array}{ccc}a11&a12&a13\\a21&a22&a23\end{array}\right]

usando a formula aij=(1+j)²
a11= (1+1)²=4
a12=(1+2)²=9
a13=(1+3)²=16
a21=(2+1)²=9
a22=(2+2)²=16
a23=(2+3)²=25

A=  \left[\begin{array}{ccc}4&9&16\\9&16&25\end{array}\right]
2 3 2
  • PeH
  • Ambicioso
2013-08-19T23:30:49-03:00